10y^2-4y+3=0

Solution for 10y^2-4y+3=0 equation:

Simplifying
10y2 + -4y + 3 = 0

Reorder the terms:
3 + -4y + 10y2 = 0

Solving
3 + -4y + 10y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
0.3 + -0.4y + y2 = 0

Move the constant term to the right:

Add '-0.3' to each side of the equation.
0.3 + -0.4y + -0.3 + y2 = 0 + -0.3

Reorder the terms:
0.3 + -0.3 + -0.4y + y2 = 0 + -0.3

Combine like terms: 0.3 + -0.3 = 0.0
0.0 + -0.4y + y2 = 0 + -0.3
-0.4y + y2 = 0 + -0.3

Combine like terms: 0 + -0.3 = -0.3
-0.4y + y2 = -0.3

The y term is -0.4y.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4y + 0.04 + y2 = -0.3 + 0.04

Reorder the terms:
0.04 + -0.4y + y2 = -0.3 + 0.04

Combine like terms: -0.3 + 0.04 = -0.26
0.04 + -0.4y + y2 = -0.26

Factor a perfect square on the left side:
(y + -0.2)(y + -0.2) = -0.26

Can't calculate square root of the right side.

The solution to this equation could not be determined.